The mass of CaCl2 formed when 5 mole of chlorine reacts with calcium metal is 140 g.
This can be calculated using the following equation:
Mass of CaCl2 = (5 mol Cl x 70.9 g/mol Cl) + (5 mol Ca x 40.1 g/mol Ca) = 140 g
Calculate the mass of CaCl2 formed when 5 mole of chlorine reacts with calcium metal
3 answers
calculete the mass of CaCL2 formed when 5 moles of chlorine reacts with calcium metal. solution
use;- ca + cl2 =cacl2 (at. weight ca =40gm,cl=35.5gm)
use;- ca + cl2 =cacl2 (at. weight ca =40gm,cl=35.5gm)
The balanced equation for the reaction between calcium and chlorine is:
Ca + Cl2 -> CaCl2
The molar ratio between calcium and chlorine is 1:2, which means that for every mole of calcium used, 2 moles of chlorine are required to completely react. Therefore, if 5 moles of chlorine are used, then we need 2.5 moles (5/2 = 2.5) of calcium to completely react with all the chlorine.
The molar mass of CaCl2 is 40.1 + 2(35.5) = 111.1 g/mol.
The mass of CaCl2 formed can be calculated using:
mass = moles x molar mass
mass = 2.5 mol x 111.1 g/mol
mass = 277.75 g
Therefore, 277.75 g of CaCl2 will be formed when 5 moles of chlorine react with calcium metal.
Ca + Cl2 -> CaCl2
The molar ratio between calcium and chlorine is 1:2, which means that for every mole of calcium used, 2 moles of chlorine are required to completely react. Therefore, if 5 moles of chlorine are used, then we need 2.5 moles (5/2 = 2.5) of calcium to completely react with all the chlorine.
The molar mass of CaCl2 is 40.1 + 2(35.5) = 111.1 g/mol.
The mass of CaCl2 formed can be calculated using:
mass = moles x molar mass
mass = 2.5 mol x 111.1 g/mol
mass = 277.75 g
Therefore, 277.75 g of CaCl2 will be formed when 5 moles of chlorine react with calcium metal.
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