The balanced chemical equation for the reaction between chlorine and calcium is:
Ca + Cl2 → CaCl2
From the equation, we can see that 1 mole of calcium reacts with 1 mole of chlorine to form 1 mole of calcium chloride. Therefore, if 8 moles of chlorine react, we need 8 moles of calcium to react as well.
The molar mass of CaCl2 is 110.98 g/mol (40.08 g/mol for calcium and 2x 35.45 g/mol for chlorine). So, to find the mass of CaCl2 formed, we can use:
mass = moles x molar mass
mass = 8 moles x 110.98 g/mol
mass = 887.84 g
Therefore, 887.84 grams of CaCl2 will be formed when 8 moles of chlorine reacts with calcium metal.
How many grams of cacl2 formed when 8 moles of chlorine reacts with calcium metal?
1 answer