Calculate the amount in moles and the mass in grams of KOH needed to convert 1.50 g of aluminum to KAl(OH)4. Balanced equation = 2 Al (s) + 2 KOH (aq) + 6 H2O (l)-2 KAl(OH)4 (aq) + 3 H2 (g)

Question

Calculate the amount in moles and the mass in grams of KOH needed to convert 1.50 g of aluminum to KAl(OH)4. Balanced equation = 2 Al (s) + 2 KOH (aq) + 6 H2O (l)->2 KAl(OH)4 (aq) + 3 H2 (g)

DrBob222 · Answer

You work this the same way as the alum problem I did above.

Cynthia · Answer

Which one ?

DrBob222 · Answer

http://www.jiskha.com/display.cgi?id=1330564841