Asked by Cynthia
What how can I calculate the amount in moles and the mass in grams of KOH needed to convert 1.50 g of aluminum to KAl(OH)4. Balanced equation = 2 Al (s) + 2 KOH (aq) + 6 H2O (l)->2 KAl(OH)4 (aq) + 3 H2 (g)
Please show steps ..
Please show steps ..
Answers
Answered by
DrBob222
mols Al = grams/atomic mass
Use the coefficients in the balanced equation to convert mols Al to mols KOH.
Then convert mols KOH to g. g = mols x molar mass.
All of these are done this same way with these three steps. (Sometimes the first step is mols = M x L if it is a soln. Sometimes they stick a percent yield at the end. But basically these three steps will do it.)
Use the coefficients in the balanced equation to convert mols Al to mols KOH.
Then convert mols KOH to g. g = mols x molar mass.
All of these are done this same way with these three steps. (Sometimes the first step is mols = M x L if it is a soln. Sometimes they stick a percent yield at the end. But basically these three steps will do it.)
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