Calculate the amount in moles and the mass in grams of KOH needed to convert 1.50 g of aluminum to KAl(OH)4. Balanced equation = 2 Al (s) + 2 KOH (aq) + 6 H2O (l) �¨ 2 KAl(OH)4 (aq) + 3 H2 (g)

Answer 1

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