since 16=4^2, log_4 = 2log_16
so, converting all to base 4 logs,
log4(2) + 1/2 log4(2)
Since 2 = √4, log4(2) = 1/2, and we have
1/2 + 1/2 (1/2) = 1/2 + 1/4 = 3/4
or, looking at it another way,
2 = √4, so log4(2) = 1/2
2 = ∜16, so log16(2) = 1/4
1/2 + 1/4 = 3/4
Calculate Directly
Log (base 4) 2 + log (base 16) 2
1 answer