Block B has a mass of 4.50kg and is moving to the left at a speed of 4.50m/s. Block A has a mass of 6.50kg and is moving to the right. The two blocks undergo a perfectly inelastic collision. What should the velocity of the Block A be in order to have the two blocks move to the right with a speed of 1.20 m/s after the collision?

Answer 1

conserve momentum:

4.50(-4.50) + 6.50v = (4.50+6.50)(+1.20)