Asked by iqbal
a block of mass 50kg just slide distance of one metre if the coefficient of friction between their surface is 0.2,then work done against friction is
Answers
Answered by
Henry
Wb = M*g = 50 * 9.8 = 490 N. = Normal
force, Fn.
Fk = u*Fn = 0.2 * 490 = 98 N.
Work = Fk*d = 98 * 1 = 98 J.
force, Fn.
Fk = u*Fn = 0.2 * 490 = 98 N.
Work = Fk*d = 98 * 1 = 98 J.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.