Note that this reaction will not occur. I don't know if you made it up or a teacher gave it to you but it doesn't meet any of the criteria for a reaction to occur. However, for the puroses of answering your questions about stoichiometry we will assume it will occur. I will round all of my calculations and the molar masses so you will need to go through and recalculate each step. My final answer will be approximate only.
Fe2(S04)3 + 6NaCl ==> 2FeCl3 + 3Na2S04
a. moles in 75 g FeCl3 = grams/molar mass = 75/162 = 0.5
Convert to moles NaCl needed. Use the coefficients in the balanced equation.
0.5 moles FeCl3 x (6 mols NaCl/2 mols FeCl3) = 0.5 x 3 = 0.15
Grams NaCl = mols NaCl x molar mass NaCl = ?
b. c. b is worked the same as a. c follows the same guidelines.
Post your work if you get stuck.
Based on the following chemical equation, balance the equation an answer the following questions:
Fe2(S04)3 + NaCl ( FeCl3 + Na2S04
Calculate the amount in grams of NaCl needed to produce 75 g of FeCl3.
Calculate the amount of Fe2(S04)3 in grams produce 215 g Na2S04.
Calculate the number of formula units of FeCl3 produced with 95g of Fe2(S04)3.
1 answer
1 answer