To balance the given chemical equation:
\[ \text{BaO}_2 + \text{H}_2\text{SO}_4 \rightarrow \text{H}_2\text{O}_2 + \text{BaSO}_4 \]
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Count the number of atoms for each element on both sides of the equation:
- Reactants:
- Ba: 1 (from BaO2)
- O: 2 (from BaO2) + 4 (from H2SO4) = 6
- H: 2 (from H2SO4)
- S: 1 (from H2SO4)
- Products:
- H: 2 (from H2O2)
- O: 2 (from H2O2) + 4 (from BaSO4) = 6
- Ba: 1 (from BaSO4)
- S: 1 (from BaSO4)
- Reactants:
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Balance the equation:
- Both sides have the same number of Ba (1), S (1), and O (6) atoms as well as H (2).
It appears that all elements are already balanced. Thus, the coefficients that balance the chemical equation are:
(1) BaO2 + (1) H2SO4 → (1) H2O2 + (1) BaSO4
So the balanced equation is:
\[ 1 \text{BaO}_2 + 1 \text{H}_2\text{SO}_4 \rightarrow 1 \text{H}_2\text{O}_2 + 1 \text{BaSO}_4 \]
Coefficients: (1), (1), (1), (1).