First, I have no idea what Chapter 8 says.
For question 1, your answers look ok although I wouldn't have answered them exactly as you did. For example, I think ErF3 is reduced. Although 2ErF3 isn't wrong, at least I wouldn't count that wrong on an exam, I would omit the 2. Same for the other answers.
For 2.
Since I've told you that your answers are ok for 1, 2 is done the same way.
For two questions below, first write and balance the equation for the chemical reaction. Please, also review the material in Chapter 8, if you will feel you might need it in order to answer the questions.
Next, please answer the following questions:
(a) What substance is reduced?
(b) What is the reducing agent?
(c) What substance is oxidized?
(d) What is the oxidizing agent?
Question 1: Erbium metal (Er) can be prepared by reacting erbium(III) fluoride with magnesium; the other product is magnesium fluoride.
2 ErF3 + 3 Mg → 3 MgF2 + 2 Er
a) 2ErF3
b) 3Mg is oxidized to 3MgF2
c) 3Mg
d) 2ErF3 is reduced to 2Er
Question 2: Europium (Eu) is used in older television screens to give a red color. The metal can be prepared by electrolysis of molten europium(III) chloride; chlorine gas is a by-product.
2EuCl3 --> 2Eu + 3Cl2
a)
b)
c)
d)
Not sure what I have right or wrong. need help please.
1 answer