Ba(NO3)2(aq) + Na2SO4(aq) → BaSO4(s) + 2NaNO3(aq)

Question

An experiment was begun with 75.00 g of Ba(NO3)2 and an excess of Na2SO4. After collecting and drying the product, 64.45 g of BaSO4 was obtained. Calculate the theoretical yield and percentage yield of BaSO4.

Answer 1

Ba(NO3)2(aq) + Na2SO4(aq) → BaSO4(s) + 2NaNO3(aq)
mols Ba(NO3)2 = grams/molar mass = ?
How much BaSO4 will be produced? Since 1 mol Ba(NO3)2 will produce 1 mol BaSO4, you will produce mols BaSO4 = mols Ba(NO3)2.
Convert mols Ba(NO3)2 to grams. grams = mols x molar mass = ? This is the theoretical yield (TY). You collected 64.45 g which is the actual yield (AY).
Then % yield = (AY/TY) * 100 = ?