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Ba(NO3)2(aq) + Na2SO4(aq) → BaSO4(s)

Barium sulfate, BaSO4 is made by the following reaction.Ba(NO3)2(aq) + Na2SO4(aq)----> BaSO4(s) + 2NaNO3(aq) An experiment was
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2. asked by David
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Barium sulfate forms as a precipitate in the following reaction:Ba(NO3)2 (aq) + Na2SO4 (aq) -> BaSO4 (s) + 2NaNo3 (aq) When
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2. asked by Anonymous
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Ba(NO3)2(aq) + Na2SO4(aq) → BaSO4(s) + 2NaNO3(aq)An experiment was begun with 75.00 g of Ba(NO3)2 and an excess of Na2SO4.
1. 1 answer
2. asked by Pickles
3. 4,463 views
What volume (in mL) of 0.45 M Na2SO4 solution is needed to precipitate all the barium, as BaSO4(s), from 14.5 mL of 0.15 M
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2. asked by John
3. 647 views
Given the reaction at equilibrium:BaSO4(s) ↔ Ba2+(aq) + SO42–(aq) BaSO4<--> Ba2+. + SO42- The concentration of SO42– ions
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2. asked by Carolina
3. 4,810 views
How many moles of BaSO4 are formed if 0.5 moles of Na2SO4 react with excess BaCl2?Na2SO4 + BaCl2 → BaSO4 + 2NaCl A. 0.144 mol
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2. asked by akarsha
3. 42 views
What is produced during the replacement reaction of Ba(NO3)2 and Na2SO4?2BaNa + 2NO3SO4 2NaNO3 + BaSO4 NaNO3 + BaSO4 BaNa2 +
1. 1 answer
2. 14 views
5. A 0.500 g sample of a BaCl2•2H2O/Na2SO4 salt mixture, when mixed with water, filtered, and dried, produced 0.225 g of
1. 2 answers
2. asked by sarah
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In the lab, you mix 30mL of 0.30M Na2SO4 with 10mL of 0.25M Ba(OH)2 to produce BaSO4 and NaOH. Calculate the theoretical yield
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2. asked by Liyah
3. 476 views
A 0.500 g sample of a BaCl2•2H2O/Na2SO4 salt mixture, when mixed with water,filtered, and dried, produced 0.225 g of BaSO4.
1. 2 answers
2. asked by emma
3. 562 views