Asked by Carolina
Given the reaction at equilibrium:
BaSO4(s) ↔ Ba2+(aq) + SO42–(aq)
BaSO4<--> Ba2+. + SO42-
The concentration of SO42– ions can be decreased by the addition of
A) BaSO4(s)
B) BaCl2(s)
C) Na2SO4(s)
D) NaNO3(s)
BaSO4(s) ↔ Ba2+(aq) + SO42–(aq)
BaSO4<--> Ba2+. + SO42-
The concentration of SO42– ions can be decreased by the addition of
A) BaSO4(s)
B) BaCl2(s)
C) Na2SO4(s)
D) NaNO3(s)
Answers
Answered by
DrBob222
B
Adding BaCl2 will increase the (Ba^2+) and that will shift the solubility of
BaSO4(s) ==> Ba^2+ + [SO4]^2- to the left so more BaSO4 will ppt. That will decrease the [SO4]^2-
Adding BaCl2 will increase the (Ba^2+) and that will shift the solubility of
BaSO4(s) ==> Ba^2+ + [SO4]^2- to the left so more BaSO4 will ppt. That will decrease the [SO4]^2-