At the instant the displacement of a 2.00 kg object relative to the origin is d = (2.00 m) + (4.00 m) - (3.00 m) , its velocity is v = - (5.50 m/s) + (2.90 m/s) + (3.20 m/s) , and it is subject to a force F = (5.70 N) - (7.80 N) + (3.80 N) .

Question

At the instant the displacement of a 2.00 kg object relative to the origin is d = (2.00 m)  + (4.00 m)  - (3.00 m) , its velocity is v = - (5.50 m/s)  + (2.90 m/s)  + (3.20 m/s) , and it is subject to a force F = (5.70 N)  - (7.80 N)  + (3.80 N) . 
(a) Find the acceleration of the object.
( 1 m/s2)  + ( 2 m/s2)  + ( 3 m/s2)

(b) Find the angular momentum of the object about the origin.
( 4 kg · m2/s)  + ( 5 kg · m2/s)  + ( 6 kg · m2/s)

(c) Find the torque about the origin acting on the object.
( 7 N · m)  + ( 8 N · m)  + ( 9 N · m)

(d) Find the angle between the velocity of the object and the force acting on the object.
10°