At the instant the displacement of a 2.00 kg object relative to the origin is d = (2.00 m) ihat + (4.00 m) jhat - (3.00 m) khat, its velocity is v = - (6.20 m/s) ihat + (2.70 m/s) jhat + (2.60 m/s) khat, and it is subject to a force F = (6.00 N) ihat - (7.70 N) jhat + (4.10 N) khat.
(a) Find the acceleration of the object.
The jhat, khat, and the ihat.
(b) Find the angular momentum of the object about the origin.
The jhat, khat, and the ihat.
(c) Find the torque about the origin acting on the object.
The jhat, khat, and the ihat.
(d) Find the angle between the velocity of the object and the force acting on the object.
The jhat, khat, and the ihat.
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