Assuming 100% dissociation, calculate the freezing point and boiling point of 1.96 m SnCl4 (aq)

Answer 1

delta T = i*Kf*m
i = 5 from 5 particles of SnCl4.
m = molality = 1.96
Kf = constant for water = 1.86 degrees C/m
delta T = 5*1.86*1.96
new freezing point for water is zero C - delta T.

delta T = i*Kb*m
Kb = 0.512 degrees C/m for water
Substitute into the equation and solve for delta T.
new boiling point is 100 + delta T