delta T = i*Kf*m
i = 5 from 5 particles of SnCl4.
m = molality = 1.96
Kf = constant for water = 1.86 degrees C/m
delta T = 5*1.86*1.96
new freezing point for water is zero C - delta T.
delta T = i*Kb*m
Kb = 0.512 degrees C/m for water
Substitute into the equation and solve for delta T.
new boiling point is 100 + delta T
Assuming 100% dissociation, calculate the freezing point and boiling point of 1.96 m SnCl4 (aq)
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