delta T = i*Kf*m
Substitute into the equation and solve for delta T, then subtract from 0c to find the new freezing point. i for AgNO3 is 2.
same thing for delta T = i*Kb*m but ADD delta T to normal boiling point of H2O to find the new boiling point.
m = mols/kg solvent = ?
Assuming 100% dissociation, calculate the freezing point and boiling point of 0.700 mol of AgNO3 in 1.00 kg of water.
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