Asked by JR.
Answer the following questions based on 2NH3->N2+3H2+450Joules
How much heat is released in the equation: 6NH3->3N2+9H2
What is the heat of the reaction: H2+1/3N2->2/3NH3
How much heat is released in the equation: 6NH3->3N2+9H2
What is the heat of the reaction: H2+1/3N2->2/3NH3
Answers
Answered by
DrBob222
Equation 2 is 3x that of 1; therefore, the heat released is 3x450 J.
Equation 3 is 1/3 of the reversed equation 1; therefore, the heat absorbed is 1/3 x 450J.
Equation 3 is 1/3 of the reversed equation 1; therefore, the heat absorbed is 1/3 x 450J.
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