Question
N2 (g) + 3H2 (g) → 2NH3(g) ΔH = -92.2 kJ
What mass of ammonia is theoretically produced if the above reaction released 168 kJ of heat?
What mass of ammonia is theoretically produced if the above reaction released 168 kJ of heat?
Answers
Kim
q = -168 kj
delta H= -92.2 kj/mol
n=?
n= -q/ delta H
n= -168 kj / -92.2
n= 1.82
n= m/Molar mass of NH3
m= n* MM
m= 1.82 moles * 17.03 g/mole
m= 31.02 g
Therefore, approx . 31.02 grams of NH3 is produced
delta H= -92.2 kj/mol
n=?
n= -q/ delta H
n= -168 kj / -92.2
n= 1.82
n= m/Molar mass of NH3
m= n* MM
m= 1.82 moles * 17.03 g/mole
m= 31.02 g
Therefore, approx . 31.02 grams of NH3 is produced
DrBob222
I don't buy 31.02 g. The correct answer is approx 62 g NH3 or
92.2 kJ will produce 34 g NH3 so 168 will produce 34 x 168/92.2 = ?
OR, in your work you show 1.82 and that 1.82 x 2*17.03 is correct because there is a coefficient of 2 for NH3 in the reaction.
92.2 kJ will produce 34 g NH3 so 168 will produce 34 x 168/92.2 = ?
OR, in your work you show 1.82 and that 1.82 x 2*17.03 is correct because there is a coefficient of 2 for NH3 in the reaction.