Asked by jordan
Calculate the value of Keq for the following equation.
Heat + N2(g) + 3H2(g) ↔ 2NH3(g)
[N2] = .533M
[H2] = 1.600M
[NH3] = 0.933M
Bob if you're here, can you tell me if adding a substance like "Heat" to the equation changes the whole problem? Or does it have no effect.
Heat + N2(g) + 3H2(g) ↔ 2NH3(g)
[N2] = .533M
[H2] = 1.600M
[NH3] = 0.933M
Bob if you're here, can you tell me if adding a substance like "Heat" to the equation changes the whole problem? Or does it have no effect.
Answers
Answered by
DrBob222
Adding heat to the equation has no effect on calculating this BECAUSE heat is not in the Keq constant.
Keq = (NH3)^2/(N2)(H2)^3 ; note no heat in Keq.
Just plug in the numbers and solve for Keq. A word of caution. The problem does NOT say the system is at equilibrium. You must assume it is at equilibrium in order to use those numbers in the calculation.
Back to the heat being added. That tells you two things. One is that it is an endothermic reaction (needs heat to go) AND it tells you which way the equilibrium will shift if heat is added to the system or taken out of the system.
Keq = (NH3)^2/(N2)(H2)^3 ; note no heat in Keq.
Just plug in the numbers and solve for Keq. A word of caution. The problem does NOT say the system is at equilibrium. You must assume it is at equilibrium in order to use those numbers in the calculation.
Back to the heat being added. That tells you two things. One is that it is an endothermic reaction (needs heat to go) AND it tells you which way the equilibrium will shift if heat is added to the system or taken out of the system.
Answered by
jordan
thank you.
There are no AI answers yet. The ability to request AI answers is coming soon!