Asked by Hannah
I am trying to calculate my percent error for an experiment conducted. I need to compare my average density calculated to the accepted average density but I am having trouble doing this because of the conversions.
My average density was 0.12 g/mm^3. The accepted value is for iron which is 7.8 X 10^3 kg/m^3.
So to get 0.12 g to kg I multiplied by 1000 and got 120.
Then I subtracted 120 from 7.80 X 10^3.
Is this correct so far??
My average density was 0.12 g/mm^3. The accepted value is for iron which is 7.8 X 10^3 kg/m^3.
So to get 0.12 g to kg I multiplied by 1000 and got 120.
Then I subtracted 120 from 7.80 X 10^3.
Is this correct so far??
Answers
Answered by
Steve
You got it backwards:
0.12kg is 120g
0.12g = 0.00012kg
.12g * 1kg/1000g = .00012kg
0.12kg is 120g
0.12g = 0.00012kg
.12g * 1kg/1000g = .00012kg
Answered by
Steve
Oops. Forgot to include the volume:
.12g/mm^3 * 1kg/1000g * 1m^3/(1000mm)^3 = 120000kg/m^3
.12g/mm^3 * 1kg/1000g * 1m^3/(1000mm)^3 = 120000kg/m^3
Answered by
Hannah
Oh ok so now to find the percent error do I subtract 120,000 from 7800 and then multiply by 100?
Answered by
Steve
well, if the correct value is 10, and you get 12, then the percent error is (12-10)/10 * 100 = 20%
Yours is figured the same way, but the values are so different, I wonder whether there is something wrong here.
Yours is figured the same way, but the values are so different, I wonder whether there is something wrong here.
Answered by
Hannah
Yes my data is probably wrong I'm just not sure where I messed up
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.