Asked by Hannah
For an experiment on specific heat capacities of metal in physics, I am trying to calculate my percent error but am having some trouble.
After collecting my experimental data for c (cal/g) for the object that was used which was aluminum my results are:
trial 1 = .19
trial 2 = .22
trial 3 = .26
Average = .22
Then I have to calculate the deviation for each one:
Trial 1 = -.03
Trial 2 = 0
Trial 3 = 0.04
Average = 0.005
The accepted value for aluminum is 0.22 so I took [0.005 - .22] / .22 = 97.7%. I did not think that my error would be this high. Did I make a mistake somewhere?
Thank you for your help!
After collecting my experimental data for c (cal/g) for the object that was used which was aluminum my results are:
trial 1 = .19
trial 2 = .22
trial 3 = .26
Average = .22
Then I have to calculate the deviation for each one:
Trial 1 = -.03
Trial 2 = 0
Trial 3 = 0.04
Average = 0.005
The accepted value for aluminum is 0.22 so I took [0.005 - .22] / .22 = 97.7%. I did not think that my error would be this high. Did I make a mistake somewhere?
Thank you for your help!
Answers
Answered by
Hannah
Please disregard. I figured out my mistake.
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