Convert 36.1 g Fe2O3 to g Fe3O4.
36.1 x (2*molar mass Fe3O4/3*molar mass Fe2O3) = ? g Fe3O4.
% Fe3O4 = (g Fe3O4/60.67)*100 = ?
An ore contains Fe3O4 and no other iron. The iron in a 60.67 gram sample of the ore is all converted by a series of chemical reactions to Fe2O3. The mass of Fe2O3 is measured to be 36.1 grams. What was the percent Fe3O4 in the sample of ore?
Answer in units of %
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