amount of iron in product
37.9g*(2* 55.84/(2* 55.84+16*3)(
how much Fe3O4 would this iron make?
moles Fe= (massironabove/55.84)
mole O= molesFe * 4/3
mass fe304=(2* moles Fe above+ 4 moles O above)* molemass Fe#O4)
percent Fe3O4 in ore= massFe3O4/65.46
An ore contains Fe3O4 and no other iron. The
iron in a 65.46 gram sample of the ore is all
converted by a series of chemical reactions to
Fe2O3. The mass of Fe2O3 is measured to be
37.9 grams. What was the percent Fe3O4 in
the sample of ore?
Answer in units of %
1 answer
1 answer