An object falling under the pull of gravity is acted upon by a frictional force of air resistance. The magnitude of this force is approximately proportional to the speed of the object, which can be written as f = bv. Assume b = 19 kg/s and m = 59 kg.

Question

An object falling under the pull of gravity is acted upon by a frictional force of air resistance. The magnitude of this force is approximately proportional to the speed of the object, which can be written as f = bv. Assume b = 19 kg/s and m = 59 kg. 
What is the terminal speed the object reaches while falling?

bobpursley · Accepted Answer

at terminal speed, forcegravity=forcefriction mg=19v solve for v.