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An object falling under the pull of gravity is acted upon by a frictional force of air resistance. The magnitude of this force...Asked by polo Q
                An object falling under the pull of gravity is acted upon by a frictional force of air resistance. The magnitude of this force is approximately proportional to the speed of the object, which can be written as f = bv. Assume that b = 14 kg/s and m = 41 kg. 
(a) What is the terminal speed that the object reaches while falling?
1 m/s(b)
Does your answer to part (a) depend on the initial speed of the object?
            
            
        (a) What is the terminal speed that the object reaches while falling?
1 m/s(b)
Does your answer to part (a) depend on the initial speed of the object?
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                    Answered by
            lkl
            
    lklkk
    
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