An isosceles triangle has area of 125 ft2. If the base is 14 ft, what is the length of each leg? Round your answer to the nearest tenth.

Answer 1

let the height be h
(1/2)(14)h = 125
h = 125/7

side^2 = (125/7)^2 + 7^2 = 367.877551
side = 19.18

so the two equal sides are appr. 19.2 ft each

Answer 2

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Answer 3

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Answer 4

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