a rectangle with side of 6 cm and 5 cm has the same area as an isosceles triangle with base length 12 cm find the altitude to the base of the triangle and the sides of the triangle

Answer 1

So we need a triangle with area of 30 cm^2

let the length of each of the equal sides of the isosceles triangle be x, and the height be h
h^2 + 6^2 = x^2 **

but we also know that the area of the triangle is
(1/2)(12)h = 30
6h = 30
h = 5

then in **
25 + 36 = x^2
x^2 = 61
x = √61

altitude to the base of the triangle is 5 cm
the length of each of the equal sides is √61 cm