The perimeter of an isosceles triangle is at least 56 inches. The base is twice the length of one of the sides of equal measurement of the isosceles triangle. What is the least possible value of the base of the triangle?

2 answers

2*x + 2x >= 56
solve for 2x
This is either a typo or a trick question
If the equal sides add up to the length of the base, it is not a triangle but a line.
a = 56/4 = 14 minimum
base = 14+14 = 28 at least
because if the perimeter is >56 then the base can be longer.