An intravenous saline solution contains 147 mEq/L each of Na+ and CI-

Question

How many moles of CI- are in 0.700 L of the saline solution?

Answer 1

To find the number of moles of Cl- in 0.700 L of the saline solution, we first need to calculate the concentration of Cl- in moles per liter.

Since the concentration of Cl- is 147 mEq/L, and 1 mole is equal to 1000 milliequivalents, we can convert the concentration to moles per liter:

Concentration of Cl- = 147 mEq/L * (1 mole / 1000 milliequivalents) = 0.147 moles/L

Now we can calculate the number of moles of Cl- in 0.700 L of the saline solution:

Number of moles of Cl- = Concentration of Cl- * Volume of solution
= 0.147 moles/L * 0.700 L
= 0.1029 moles

Therefore, there are approximately 0.1029 moles of Cl- in 0.700 L of the saline solution.