An intravenous saline solution contains 147 mEq/L each of Na+ and CI-

Question

How many moles of CI-
are in 0.700 L of the saline solution?

Answer 1

To find the number of moles of CI- in 0.700 L of the saline solution, we first need to find the number of moles of CI- in 1 L of the solution.

Since the solution contains 147 mEq/L of CI-, and 1 mole of CI- is equal to 1 Eq, then 147 mEq/L of CI- is equal to 147 moles/L.

Therefore, in 0.700 L of the saline solution, there would be 0.700 L * 147 moles/L = <<0.700*147=102.9>>102.9 moles of CI-.