An intravenous saline solution contains 147 mEq/L each of Na+ and CI-

Question

How many moles of Na+ are in 0.700 L of the saline solution?

Answer 1

To calculate the number of moles of Na+ in 0.700 L of the saline solution, we need to multiply the concentration of Na+ (147 mEq/L) by the volume of solution (0.700 L) and then convert from milliequivalents (mEq) to moles.

Step 1: Calculate the amount of Na+ in milliequivalents (mEq).
Concentration of Na+ in the saline solution = 147 mEq/L
Volume of saline solution = 0.700 L
Amount of Na+ in mEq = concentration * volume
= 147 mEq/L * 0.700 L
= 102.9 mEq

Step 2: Convert mEq to moles.
1 mole of Na+ = 1 equivalent (Eq)
1 mEq = 1/1000 Eq
So, 102.9 mEq = 102.9/1000 Eq

To calculate the number of moles, we divide by the Faraday constant (F), which is approximately equal to 96485 C/mol.

Number of moles of Na+ = (102.9/1000 Eq) / 96485 C/mol
= 0.001066 mol

Therefore, there are approximately 0.001066 moles of Na+ in 0.700 L of the saline solution.