An emergency plumber charges $65 per visit plus an additional $75 per hour. He arrives at Xavien’s house at 9:30 p.m. and works to repair a water leak. The total repair bill Xavien pays is $196.25.(1 point)

Question

Write an equation which can be used to determine the total hours, h, the plumber took to repair the leak.

$$h+=

What time did the plumber repair the leak?

$$

Answer 1

To find the total hours \( h \) the plumber took to repair the leak, we can use the information given. The plumber charges a flat fee for the visit and an hourly rate:

1. The initial visit fee is $65.
2. The hourly charge is $75 per hour.
3. The total bill is $196.25.

The equation can be set up as:

\[ \text{Total bill} = \text{Visit fee} + (\text{Hourly rate} \times \text{Hours worked}) \]

Plugging in the values, we get:

\[ 196.25 = 65 + 75h \]

To solve for \( h \), we first subtract the visit fee from both sides:

\[ 196.25 - 65 = 75h \]

Calculating the left side gives:

\[ 131.25 = 75h \]

Now, divide both sides by 75 to isolate \( h \):

\[ h = \frac{131.25}{75} \]

Calculating that yields:

\[ h = 1.75 \]

So the plumber worked for \( 1.75 \) hours.

To find the time the plumber finished the repair, we can add \( 1.75 \) hours to the time he arrived at 9:30 p.m.

1.75 hours is equivalent to 1 hour and 45 minutes.

Starting from 9:30 p.m.:

• Adding 1 hour brings us to 10:30 p.m.
• Adding 45 minutes brings us to 11:15 p.m.

Thus, the plumber finished the repair at:

\[ \text{11:15 p.m.} \]

In summary, the equation is:

\[ h = \frac{196.25 - 65}{75} \]

The plumber finished repairing the leak at 11:15 p.m.