To determine the total hours \( h \) the plumber took to repair the leak, we can start by formulating the equation based on the charges.
The total bill consists of two parts:
- A fixed charge for the visit: $65
- An hourly charge: $75 per hour for \( h \) hours.
The total bill can be represented by the equation:
\[ 65 + 75h = 196.25 \]
Now, we can solve for \( h \):
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Subtract 65 from both sides: \[ 75h = 196.25 - 65 \] \[ 75h = 131.25 \]
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Divide both sides by 75: \[ h = \frac{131.25}{75} \] \[ h = 1.75 \]
So, the plumber took \( 1.75 \) hours to repair the leak.
To find the time he finished the repair:
- He arrived at 9:30 p.m.
- \( 1.75 \) hours is equivalent to 1 hour and 45 minutes.
- Adding this to 9:30 p.m.:
Starting with 9:30 p.m.: 1 hour later: 10:30 p.m. 45 minutes later: 11:15 p.m.
Thus, the plumber finished the repair at 11:15 p.m.