An emergency plumber charges $65 per visit plus an additional $75 per hour. He arrives at Xavien’s house at 9:30 p.m. and works to repair a water leak. The total repair bill Xavien pays is $196.25.(1 point)

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What time did the plumber repair the leak?

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Remaining Attempts : 3

1 answer

To find out what time the plumber finished the repairs, we first need to determine how many hours he worked.

The plumber charges a base fee of $65 for the visit plus $75 for each hour worked. The total bill can be expressed with the equation:

\[ \text{Total Bill} = \text{Base Fee} + (\text{Hourly Rate} \times \text{Hours Worked}) \]

Plugging in the known values:

\[ 196.25 = 65 + (75 \times \text{Hours Worked}) \]

Now, subtract the base fee from the total bill:

\[ 196.25 - 65 = 75 \times \text{Hours Worked} \]

This simplifies to:

\[ 131.25 = 75 \times \text{Hours Worked} \]

Next, divide both sides by 75 to solve for the hours worked:

\[ \text{Hours Worked} = \frac{131.25}{75} = 1.75 \text{ hours} \]

Now, convert 1.75 hours into hours and minutes:

1.75 hours = 1 hour and 0.75 of an hour (0.75 hours is 45 minutes).

So, the plumber worked for 1 hour and 45 minutes.

Since he arrived at Xavien's house at 9:30 p.m., we add 1 hour and 45 minutes to that time:

  • 9:30 p.m. + 1 hour = 10:30 p.m.
  • 10:30 p.m. + 45 minutes = 11:15 p.m.

Thus, the plumber finished repairing the leak at 11:15 p.m.