max force= mg+ ma
I would add in the masses of the maximum number of passengers, that will be what needs to be lifted.
Minimum force=mg
An elevator (mass 4125 kg) is to be designed so that the maximum acceleration is 0.0400g.
What is the maximum force the motor should exert on the supporting cable?
What is the minimum force the motor should exert on the supporting cable?
5 answers
what if there are no passengers? for max force i got 330 and for the min force i got 165
max force = mga+ mg
max force = Mass x gravity( 1+ gravity)
max force =4125 x 9.8(1+9.8)
max force =42042
max force = Mass x gravity( 1+ gravity)
max force =4125 x 9.8(1+9.8)
max force =42042
min force = mg- mga
min force = mass x gravity(1- gravity)
min force =4125 x 9.8 (1- 0.04)
min force= 388808
I made a mistake for the max for the correction is max force = mass x gravity( 1 + acceleration)
Don't forget to write your answers in Newton (N)
min force = mass x gravity(1- gravity)
min force =4125 x 9.8 (1- 0.04)
min force= 388808
I made a mistake for the max for the correction is max force = mass x gravity( 1 + acceleration)
Don't forget to write your answers in Newton (N)
errrdx