Asked by Emily
An elevator (cabin mass 600 kg) is designed for a maximum load of 2700 kg, and to reach a velocity of 3.4 m/s in 5 s. For this scenario, what is the tension the elevator rope has to withstand?
I know I have to multiply the mass by the acceleration. I'm having a hard time deciphering what exactly I need to use. Please help! Thanks
I know I have to multiply the mass by the acceleration. I'm having a hard time deciphering what exactly I need to use. Please help! Thanks
Answers
Answered by
Scott
so the maximum load (cabin plus cargo) is 3300 kg
the tension is the force that will accelerate the load to .68 m/s²
this is against gravity
so the tension overcomes gravity (mg) PLUS accelerates the load
t = m g + m a = m (g + a)
...= 3300 (9.81 + .68)
the tension is the force that will accelerate the load to .68 m/s²
this is against gravity
so the tension overcomes gravity (mg) PLUS accelerates the load
t = m g + m a = m (g + a)
...= 3300 (9.81 + .68)
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