Asked by Meghan

An elevator (mass 4175 kg) is to be designed so that the maximum acceleration is 0.0700g.
What is the maximum force the motor should exert on the supporting cable?
What is the minimum?

Answers

Answered by drwls
M*(g+a) = minimum

M*(g-a) = minimum

M should include the maximum passenger load in the maximum-force case.

M should be elevator mass only in the minimum case.

Whoever assigned the problem should realize that. What school is teaching this course?

I am curious. Teaching standards and student effort have suffered since online education has become the rage.
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