Asked by DJ

An elevator (mass 4125 kg) is to be designed so that the maximum acceleration is 0.0400g.
What is the maximum force the motor should exert on the supporting cable?
What is the minimum force the motor should exert on the supporting cable?
Answered by bobpursley
max force= mg+ ma
I would add in the masses of the maximum number of passengers, that will be what needs to be lifted.
Minimum force=mg
Answered by DJ
what if there are no passengers? for max force i got 330 and for the min force i got 165
Answered by babygenise
max force = mga+ mg
max force = Mass x gravity( 1+ gravity)
max force =4125 x 9.8(1+9.8)
max force =42042
Answered by babygenise
min force = mg- mga
min force = mass x gravity(1- gravity)
min force =4125 x 9.8 (1- 0.04)
min force= 388808

I made a mistake for the max for the correction is max force = mass x gravity( 1 + acceleration)
Don't forget to write your answers in Newton (N)
Answered by Anonymous
errrdx
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