Asked by Anonymous
While an elevator of mass 2681 kg moves upward, the tension in the cable is 29.4 kN.
(a) What is the acceleration of the elevator?
(b) If at some point in the motion the velocity of the elevator is 1.04 m/s upward, what is the elevator's velocity 3.96 s later?
Please helppp and explain because I keep getting it wrong!!! Thnks
(a) What is the acceleration of the elevator?
(b) If at some point in the motion the velocity of the elevator is 1.04 m/s upward, what is the elevator's velocity 3.96 s later?
Please helppp and explain because I keep getting it wrong!!! Thnks
Answers
Answered by
bobpursley
tension= (mg+ma) solve for a.
b. Vnext= vfirst+ a t
solve for vnext
b. Vnext= vfirst+ a t
solve for vnext
Answered by
Anonymous
So would it be
29.4=(2681(9.8)+2681(a))
I don't think so cuz it gives me .001 n thtz wrong...
29.4=(2681(9.8)+2681(a))
I don't think so cuz it gives me .001 n thtz wrong...
Answered by
bobpursley
You need a tutor. Tension=ma+mg is in SI units. Tension was given as 29,400 Newtons.
You have to consider units.
You have to consider units.
Answered by
Anonymous
Oh I see...thnk you n sorry :/
Answered by
Anonymous
would the be a=-6.8 or 6.8 ???
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