Asked by Anonymous

While an elevator of mass 2681 kg moves upward, the tension in the cable is 29.4 kN.

(a) What is the acceleration of the elevator?

(b) If at some point in the motion the velocity of the elevator is 1.04 m/s upward, what is the elevator's velocity 3.96 s later?

Please helppp and explain because I keep getting it wrong!!! Thnks
Answered by bobpursley
tension= (mg+ma) solve for a.

b. Vnext= vfirst+ a t
solve for vnext
Answered by Anonymous
So would it be

29.4=(2681(9.8)+2681(a))

I don't think so cuz it gives me .001 n thtz wrong...
Answered by bobpursley
You need a tutor. Tension=ma+mg is in SI units. Tension was given as 29,400 Newtons.

You have to consider units.
Answered by Anonymous
Oh I see...thnk you n sorry :/
Answered by Anonymous
would the be a=-6.8 or 6.8 ???
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