An elevator (mass 4125 kg) is to be designed so that the maximum acceleration is 0.0300g.

Question

What is the maximum force the motor should exert on the supporting cable?
What is the minimum force the motor should exert on the supporting cable?

Answer 1

F= ma= Tension-Weight
ma+Weight=Tension
(4125kg)(0.0300 * 9.8)+ (4125kg)(9.81)=Tension

Calculate and this will give you the answer for maximum force.

For part (2)
You have to subtract them (ma-weight)