An Earth satellite moves in a circular orbit 775 km above the Earth's surface. The period of the motion is 100.1 min.

Question

(a) What is the speed of the satellite?
m/s

(b) What is the magnitude of the centripetal acceleration of the satellite?
m/s2

Answer 1

R = Rearth + 775,000 meters

speed = distance/time = 2 pi R/(100.1*60)

Ac = speed^2/R