An Earth satellite moves in a circular orbit 770 km above the Earth's surface. The period of the motion is 100.0 min. What is the speed of the satellite? What is the magnitude of the centripetal acceleration of the satellite?

Answer 1

find the distance from the center of Earth. (re+h) IN METERS

V= distance/time= 2PI*(re+h)/(100*60sec)

solve for v.

centi acceleration: m v^2/(re+h)