10 = (1/2) a t^2
20 = a (4)
a = 5 m/s^2
An athlete is training and is required to perform shuttle runs. From the starting position they sprint out to 10m (this takes 2 seconds).
Where would the maximum acceleration occur? Justify your answer.
Please help! Thankyou.
4 answers
Thankyou, but I need to establish where within the run max acceleration occurs (what metre mark?)
I suspect if they turn around at the end, the max acceleration occurs there.
I think I know what you were looking for. Starting off where Damon left off,
Max acceleration occurs when the velocity=acceleration.
Vi=0m/s^2
Vf=5m/s and
a=5m/s^2
d=?
Solve for d.
Vf^2=Vi^2+2ad
(5m/s)^2=0+2(5m/s^2)d
25=10d
25/10=d
d=2.5m
The runner establishes max acceleration at the 2.5m mark in the race.
Hope I helped in time.
Max acceleration occurs when the velocity=acceleration.
Vi=0m/s^2
Vf=5m/s and
a=5m/s^2
d=?
Solve for d.
Vf^2=Vi^2+2ad
(5m/s)^2=0+2(5m/s^2)d
25=10d
25/10=d
d=2.5m
The runner establishes max acceleration at the 2.5m mark in the race.
Hope I helped in time.
2 answers