An archer needs to hit a bull’s eye on a target at eye level 60.0 ft away. If the archer fires the arrow from eye level with a speed of 47.0 ft/s at an angle of 25 degree above the horizontal, will the arrow hit the target?

Answer 1

convert 47 ft/s to m/s = 14.3m/s
V = 14.3 m/s
Angle = 25 degree
|Vx|=|V|cos(25)
|Vx|=|14.3 cos(25)= 13 m/s

|Vy|=|V|sin(25)
|Vy|=|14.3 sin(25)= 6.04 m/s

t= Vy x 2 /9.8
t= 6.04m/s x 2 /9.8 m/s^2 = 1.23 s

SX = VX * t

then convert it back to feet

so the arrow will miss the target as the arrow travel about 52.3 feet