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J_nin
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An archer needs to hit a bull’s eye on a target at eye level 60.0 ft away. If the archer fires the arrow from eye level with a
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convert 47 ft/s to m/s = 14.3m/s V = 14.3 m/s Angle = 25 degree |Vx|=|V|cos(25) |Vx|=|14.3 cos(25)= 13 m/s |Vy|=|V|sin(25) |Vy|=|14.3 sin(25)= 6.04 m/s t= Vy x 2 /9.8 t= 6.04m/s x 2 /9.8 m/s^2 = 1.23 s SX = VX * t then convert it back to feet so the arrow
