An archer stands 60

Question

meters (m) from a target. She launches an arrow, and it lands 3
centimeters (cm) from the bull's-eye. The archer changes her position to 40
m from the target, and her next arrow lands 2
cm from the bull's-eye. She changes her position to 20
m, and her next arrow lands 1
cm from the bull's-eye.

Which points describe the situation when the archer stands at 40
m?

Let the x-
coordinate be the archer's distance from the target in meters, and let the y-
coordinate be the arrow's distance from the bull's-eye in centimeters.

Responses

(2,40)
open paren 2 comma 40 close paren

(60,40)
open paren 60 comma 40 close paren

(40,2)
open paren 40 comma 2 close paren

(40,3)
open paren 40 comma 3 close paren

Answer 1

To describe the situation when the archer stands at 40 meters from the target, we need to represent the archer's distance from the target as the x-coordinate and the arrow's distance from the bull's-eye as the y-coordinate.

When the archer is at 40 meters from the target, the arrow lands 2 centimeters from the bull's-eye. Therefore, the coordinates will be:

• x-coordinate: 40 (the distance from the target in meters)
• y-coordinate: 2 (the distance from the bull's-eye in centimeters)

Thus, the correct point to describe the situation when the archer stands at 40 m is:

(40, 2)

So the answer is:

(40, 2)