an agriculture field is rectangular, with dimensions 100m by 42m.a 20 m deep well of diameter 14 m is dug in a corner of the field and the earth taken out is spread evenly over the remaining part of the field.find the increase in the level of the field

Answer 1

volume of well = π r^2 h
= π(7^2)(20)
= 98π m^3

surface area to be covered by dirt
= 100(42) - π(7^2)
=4200 - 49π m^2

let the depth of the dirt be h m

(4200 - 49π)h = 98π

check and do my arithmetic

Answer 2

0.076

Answer 3

76

Answer 4

You are really correct. My response is just like u.

Answer 5

Sorry , the answer is mighty 76.please help me! I am in confusion.!!!!!

Answer 6

Volume Of well=22/7×7×7×20
=3,080m^3
Area Of filed =100×42= 4200m^2
The area of the remaning part of the filed=the area of field - the area of well, so. 4200m^2 - 154m^2 (22/7×7×7)=4046m^2
The volume of the riseing filed = the volume of the earth dug out
4046(h)=3080m^3
h=0.7612'm
=76cm።።።።just like hizki..

Answer 7

yes

Answer 8

calculate the volume and surface area of a right circular cylinder of height 1m and 70cm

Answer 9

(toliyad) the answer is 76cm dude

Answer 10

The level of the field increased by 76 cm.

Answer 11

76

Answer 12

To calculate the volume of a right circular cylinder, we use the formula:

V = πr²h

where r is the radius of the base and h is the height of the cylinder.

Given: Height h = 1.7 m

The radius is not given, so we cannot calculate the volume.

To calculate the surface area of a right circular cylinder, we use the formula:

A = 2πrh + 2πr²

where r is the radius of the base and h is the height of the cylinder.

Given: Height h = 1.7 m

The radius is not given, so we cannot calculate the surface area.