A rectangular field is four times as long as it is wide. If the perimeter of the field is 750 feet, what are the dimensions of the field?

Answer 1

Let w represent the width.

2 (4w) + 2w = 750
8w + 2w = 750
10w = 750
w = 75

Answer 2

width 50 and length 200

Answer 3

Let's L=4w
2(L+w)=P
2(4w+w)=750
8w+2w=750
10w=750
W=75

Answer 4

So the width of the field is 75 feet.

To find the length, we can use L=4w.

L=4(75)
L=300

So the dimensions of the field are 75 feet by 300 feet.